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NEW! Ultracapacitor Super capacitor 3000F 2.7V 60*13 60*130C086
BRAND NEW !      

  1pcs   Cap

  Ultracapacitor

Super capacitor

   3000F 2.7V

60*13 60*130

>> FAST SHIPPING >>

RETURN POLICY : 120 DAYS

 Originally Supplied 

     With Some known Models :                     

*

 

    

  CAPACITOR

                

 >>>>>  FAST  SHIPPING   >>>

          

  C086

---------------------------------

equivalent resistance; Uwork (V) is: in the circuit in normal working voltage UMIN (V): demand minimum voltage devices; t (s): in the circuit requirements to time or pulse application of pulse duration. Udrop (V): in the end of the discharge current pulse, the total voltage drop; I (a): load current; formula for approximate calculation of the super capacitor, the formula according to, keep the need = energy super capacitor to reduce energy. Uwork+ (Umin =1/2I) t;
Uwork2 (-Umin2 =1/2C), which can be IR (Umin) It/ (-Umin*Umin Uwork*Uwork) C= (Uwork+), can be the capacity of the super capacitor.
Example: assume that the tape drive of the working voltage 5V, safe working voltage 3V. If the DC motor is required to keep the 0.5A for 2 seconds (it is safe to work), the need to use a large capacity of the super capacitor? Solution: C= (Umin Uwork+) It/ (-Umin*Umin Uwork*Uwork) = (5+3) *0.2*2 / (5*5-3*3) = 0.5F
Because the voltage of the 5V exceeds the nominal operating voltage of the capacitor. Therefore, it can be connected in series with the two capacitor. In series with the same capacitor series, the voltage of each of the two is 2.5V. If we choose the nominal capacity is 1F capacitor, the two string is 0.5F. Considering the capacity of the capacitor - 20%, the choice can not provide adequate margin. Can choose the nominal capacity is 1.5F capacitor, can provide 1.5F/2=0.75F. Considering the minimum deviation 20% capacity, 1.2F/2 = 0.6F. The super capacitor provides a sufficient safety margin. After the high current pulse, the tape drive is transferred to the small current mode, with the excess capacity of the remaining energy.
 

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Please pay as soon as possible after winning an auction, as that will allow us to post your item to you sooner!

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Your order will be dispatched within 1 working day of receiving payment (Monday-Friday) and you should expect to receive it two or three days after dispatch (for orders sent 1st Class and Priority Mail).


In the very unlikely event that your item is lost or damaged during post, then WE are responsible and will issue either a full refund or replacement.

          Returns

If you are not 100% satisfied with your purchase, you can return the product and get a full refund or exchange the product for another one, be it similar or not.


You can return a product for up to 180 days from the date you purchased it.


Any product you return must be in the same condition you received it and in the original packaging. Please keep the receipt.

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BRAND NEW ! 1pcs Cap Ultracapacitor Super capacitor 3000F 2.7V 60*13 60*130 >> FAST SHIPPING >> RETURN POLICY : 120 DAYS Originally Supplied With Some known Models : * CAPACITOR >>>>> FAST SHIPPING >>> C086 --------------------------------- equivalent resistance; Uwork (V) is: in the circuit in normal working voltage UMIN (V): demand minimum voltage devices; t (s): in the circuit requirements to time or pulse application of pulse duration. Udrop (V): in the end of the discharge current pulse, the total voltage drop; I (a): load current; formula for approximate calculation of the super capacitor, the formula according to, keep the need = energy super capacitor to reduce energy. Uwork+ (Umin =1/2I) t; Uwork2 (-Umin2 =1/2C), which can be IR (Umin) It/ (-Umin*Umin Uwork*Uwork) C= (Uwork+), can be the capacity of the super capacitor. Example: assume that the tape drive of the working voltage 5V, safe working voltage 3V. If the DC motor is required to keep the 0.5A for 2 seconds (it is safe to work), the need to use a large capacity of the super capacitor? Solution: C= (Umin Uwork+) It/ (-Umin*Umin Uwork*Uwork) = (5+3) *0.2*2 / (5*5-3*3) = 0.5F Because the voltage of the 5V exceeds the nominal operating voltage of the capacitor. Therefore, it can be connected in series with the two capacitor. In series with the same capacitor series, the voltage of each of the two is 2.5V. If we choose the nominal capacity is 1F capacitor, the two string is 0.5F. Considering the capacity of the capacitor - 20%, the choice can not provide adequate margin. Can choose the nominal capacity is 1.5F capacitor, can provide 1.5F/2=0.75F. Considering the minimum deviation 20% capacity, 1.2F/2 = 0.6F. The super capacitor provides a sufficient safety margin. After the high current pulse, the tape drive is transferred to the small current mode, with the excess capacity of the remaining energy.
High Quality
Fast Shipping

HHL STORE

Limited Time
OFFER
NEW! Ultracapacitor Super capacitor 3000F 2.7V 60*13 60*130C086
BRAND NEW !      

  1pcs   Cap

  Ultracapacitor

Super capacitor

   3000F 2.7V

60*13 60*130

>> FAST SHIPPING >>

RETURN POLICY : 120 DAYS

 Originally Supplied 

     With Some known Models :                     

*

 

    

  CAPACITOR

                

 >>>>>  FAST  SHIPPING   >>>

          

  C086

---------------------------------

equivalent resistance; Uwork (V) is: in the circuit in normal working voltage UMIN (V): demand minimum voltage devices; t (s): in the circuit requirements to time or pulse application of pulse duration. Udrop (V): in the end of the discharge current pulse, the total voltage drop; I (a): load current; formula for approximate calculation of the super capacitor, the formula according to, keep the need = energy super capacitor to reduce energy. Uwork+ (Umin =1/2I) t;
Uwork2 (-Umin2 =1/2C), which can be IR (Umin) It/ (-Umin*Umin Uwork*Uwork) C= (Uwork+), can be the capacity of the super capacitor.
Example: assume that the tape drive of the working voltage 5V, safe working voltage 3V. If the DC motor is required to keep the 0.5A for 2 seconds (it is safe to work), the need to use a large capacity of the super capacitor? Solution: C= (Umin Uwork+) It/ (-Umin*Umin Uwork*Uwork) = (5+3) *0.2*2 / (5*5-3*3) = 0.5F
Because the voltage of the 5V exceeds the nominal operating voltage of the capacitor. Therefore, it can be connected in series with the two capacitor. In series with the same capacitor series, the voltage of each of the two is 2.5V. If we choose the nominal capacity is 1F capacitor, the two string is 0.5F. Considering the capacity of the capacitor - 20%, the choice can not provide adequate margin. Can choose the nominal capacity is 1.5F capacitor, can provide 1.5F/2=0.75F. Considering the minimum deviation 20% capacity, 1.2F/2 = 0.6F. The super capacitor provides a sufficient safety margin. After the high current pulse, the tape drive is transferred to the small current mode, with the excess capacity of the remaining energy.
 

          Payment

We accept payment by any of the following methods:
PayPal


Please pay as soon as possible after winning an auction, as that will allow us to post your item to you sooner!

          Shipping

We offer SUPER FAST shipping on all orders!


Your order will be dispatched within 1 working day of receiving payment (Monday-Friday) and you should expect to receive it two or three days after dispatch (for orders sent 1st Class and Priority Mail).


In the very unlikely event that your item is lost or damaged during post, then WE are responsible and will issue either a full refund or replacement.

          Returns

If you are not 100% satisfied with your purchase, you can return the product and get a full refund or exchange the product for another one, be it similar or not.


You can return a product for up to 180 days from the date you purchased it.


Any product you return must be in the same condition you received it and in the original packaging. Please keep the receipt.

100% Guaranteed
High Quality
Fast Shipping